Y+16x=64x^2

Solution for Y+16x=64x^2 equation:

+16Y=64Y^2

We move all terms to the left:

+16Y-(64Y^2)=0

determiningTheFunctionDomain
-64Y^2+16Y=0

a = -64; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-64)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-64}=\frac{-32}{-128}
=1/4
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-64}=\frac{0}{-128}
=0
$